rip networks filtering
Think of it this way:
7 = 0000 0111 in binary.
So…
7 5 3 1
Are the numbers you are looking for.
— “Smithson, Brandon K ” wrote:
> Actually, doesn’t that just filter 1,3,5 and 7? > > Start ip = 1 = 00000001 > Mask = 6 = 00000110 > > That gives possible choices of: > 00000001 = 1 > 00000011 = 3 > 00000101 = 5 > 00000111 = 7 > > Since the starting IP is 1 and the mask has a 0 bit > in that position, > any other filtered ip must always be an odd number. > > > —–Original Message—– > From: nobody@groupstudy.com > [mailto:nobody@groupstudy.com] On Behalf Of > Edison Ortiz > Sent: Wednesday, December 19, 2007 9:11 AM > To: ‘Lora Ganeva’; ’shiran guez’ > Cc: ccielab@groupstudy.com > Subject: RE: rip networks filtering > > No, that filters network 199.16.1.0-199.16.7.255 on > the first ACL and > 199.16.8.0-.255 on the second ACL - not just even > networks. > > > > Unless I misunderstood the requirement, that should > cover it. > > > > Edison Ortiz > > Routing and Switching, CCIE # 17943 > > _____ > > From: Lora Ganeva [mailto:lganeva@mobiltel.bg] > Sent: Wednesday, December 19, 2007 9:53 AM > To: Edison Ortiz; shiran guez > Cc: ccielab@groupstudy.com > Subject: RE: rip networks filtering > > > > This filters all even networks:-( > > > > From: Edison Ortiz [mailto:edisonmortiz@gmail.com] > Sent: 19 dEKEMWRI 2007 G. 16:43 > To: Lora Ganeva; ’shiran guez’ > Cc: ccielab@groupstudy.com > Subject: RE: rip networks filtering > > > > 199.16.1.0 0.0.6.255 > > 199.16.8.0 0.0.0.255 > > > > Edison Ortiz > > Routing and Switching, CCIE # 17943 > > —–Original Message—– > From: nobody@groupstudy.com > [mailto:nobody@groupstudy.com] On Behalf Of > Lora Ganeva > Sent: Wednesday, December 19, 2007 8:44 AM > To: shiran guez > Cc: ccielab@groupstudy.com > Subject: RE: rip networks filtering > > > > Hi all, > > > > > > > > But 199.16.1.0 0.0.7.255??? this is actually > 199.16.0.0 0.0.7.255 and > the zero > > subnet has to be filtered. > > > > > > > > BR, > > > > Lora > > > > > > > > From: shiran guez [mailto:shiranp3@gmail.com] > > Sent: 19 dEKEMWRI 2007 G. 15:15 > > To: Lora Ganeva > > Cc: ccielab@groupstudy.com > > Subject: Re: rip networks filtering > > > > > > > > my mistake didnt saw the range sign > > > > > > > > Subodh given you the correct answer! > > > > On Dec 19, 2007 2:11 PM, Lora Ganeva > wrote: > > > > Hi experts, > > > > > > > > I am experiencing some problems with the following > task: > > > > > > > > Two routers , let’s say R1 and R2 are connected > (media is not important, > > let’s say it is Ethernet) > > > > > > > > R1 Eth1/0—————150.1.1.0/24————- > Eth1/0 R2 > > > > > > > > R1: > > > > > > > > Eth1/0 > > > > Ip add 150.1.1.1 255.255.255.0 > > > > > > > > > R2: > > > > Eth1/0 > > > > Ip add 150.1.1.2 255.255.255.0 > > > > > > > > > Routers are running rip and R2 is advertising the > following networks to > > R1 > > > > > > > > > > > > 199.16.0.0/24 > > > > 199.16.1.0/24 > > > > 199.16.2.0/24 > > > > 199.16.3.0/24 > > > > 199.16.4.0/24 > > > > 199.16.5.0/24 > > > > 199.16.6.0/24 > > > > 199.16.7.0/24 > > > > 199.16.8.0/24 > > > > 199.16.10.0/24 > > > > 199.16.11.0/24 > > > > 199.16.12.0/24 > > > > 199.16.13.0/24 > > > > 199.16.14.0/24 > > > > 199.16.15.0/24 > > > > > > > > The task requires by configuring only R1 (not > interface level command) > > to allow with an ACL with only 2 lines the following > subnets: > > > > > > > > > > > > 199.16.1.0/24 - 199.16.8.0/24 > > > > > > > > I have though a lot of any kind of ACLs but i still > haven’t come to a > > good solution. > > > > > > > > Any help will be appreciated, > > > > > > > > Thanks, > > > > Lora > > > >
























