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{
denotes special character to follow. Same thing with matching vlsm bits.
show ip bgp | in /23
HTH,
Scott Morris, CCIE4 (R&S/ISP-Dial/Security/Service Provider) #4713, JNCIE-M #153, JNCIS-ER, CISSP, et al. CCSI/JNCI-M/JNCI-ER VP - Technical Training - IPexpert, Inc. IPexpert Sr. Technical Instructor
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—–Original Message—– From: Athaide, Dwayne [mailto:DAthaide@eprod.com] Sent: Tuesday, December 11, 2007 11:50 AM To: Scott Morris; Chan Hong; certification Cisco Subject: RE: Regular Expression
How would you match the curl brackets in an AS-SET for example 610, {1,2}, 600 $ Thanks

—–Original Message—– From: nobody@groupstudy.com [mailto:nobody@groupstudy.com] On Behalf Of Scott Morris Sent: Tuesday, December 11, 2007 8:43 AM To: ‘Chan Hong’; ‘certification Cisco’ Subject: RE: Regular Expression
Solve it like you would a math equation… by that, things inside () are solved separately.
So:
* = 0 or more of preceeding character. [] = range representing a single character. So the * immediately follows the [0-9], which means 0 or more number values. _ = parsing character, which in an AS Path means beginning of line, space, or end of line.
So you end up with:
1 followed by 2 followed by 3 followed by 4 followed by (space or end of line). If space then you have 0 or more integer characters and then MUST have end of line. So no more spaces (extra AS numbers) can be included.
In your show command, you didn’t force the end of the string, so all of those match. it’s kind of like using “show ip bgp regexp 100″ and you will find positive results from 100, 1100, 1001, 10011, 10087, 21004, etc. because they all include the string “100″ with no other restrictions!
HTH,
Scott Morris, CCIE4 (R&S/ISP-Dial/Security/Service Provider) #4713, JNCIE-M #153, JNCIS-ER, CISSP, et al. CCSI/JNCI-M/JNCI-ER VP - Technical Training - IPexpert, Inc. IPexpert Sr. Technical Instructor
A Cisco Learning Partner - We Accept Learning Credits!
smorris@ipexpert.com

Telephone: +1.810.326.1444 Fax: +1.810.454.0130 http://www.ipexpert.com

—–Original Message—– From: nobody@groupstudy.com [mailto:nobody@groupstudy.com] On Behalf Of Chan Hong Sent: Tuesday, December 11, 2007 8:53 AM To: certification Cisco Subject: Regular Expression
Dear all,
I want to ask about regulat expression, * and [], () From my understanding, show ip bgp regxp 1234(_[0-9]*)$ will show all bgp route with as path starting from 1234 and zero or one other as in the as path (eg., 1234 4321, or 1234) But if without $, the result is all bgp routes with as path starting from 1234 and 0 or MORE other as in the as path (eg., 1234, 1234 4321, 1234 4321 4567 122) why??
$ means the end of the pattern, but which symbol mean the repeat pattern??? The * is inside (), next to [0-9]. The repeat pattern should apply on character 0-9 only. Inside the (), there is a _ also, which can be “space” or end of string. Why without the $, the show ip bgp rexp 1234(_[0-9]*) can be something like:
R1#sh ip bgp regexp 1234(_[0-9]*) BGP table version is 3, local router ID is 10.155.129.1 Status codes: s suppressed, d damped, h history, * valid, > best, i - internal, r RIB-failure, S Stale Origin codes: i - IGP, e - EGP, ? - incomplete Network Next Hop Metric LocPrf Weight Path *> 3.0.0.0 10.155.129.2 200 0 1234 103 80 i *> 8.5.250.0/24 10.155.129.4 200 0 1234 10 13 15 i *> 15.149.2.0/24 10.155.129.4 200 0 1234 10 i
Regards, Howard Yahoo! g62d8 e. e(f;g%o http://hk.promo.yahoo.com/security/index.htmld:h’#f4e$!