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EUI -64 to MAC
hey guys, am trying to understand a scenerio, and would appreciate a better explanation. task:————–Conf. IPv6 addre. 2001:192:10:1:1234:56ff:fe:78:9abc on r1 fa0/0. The host portion be gotten from eui-64.solution:—————r1#int fa0/0mac-addre 1034.5678.9abcipv6 add 2001:192:10:1::/64 eui-64 their explanation was : Invert the 7most significant bit, then remove ff:fe, this equals 1034.5678.9abc. Understandable, but the issue i have is: :when they say invert the 7most significant bit, do this mean the 7 most significant bit in the first octect?? regards, Uyota
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